&question1=What is the derivative used for?&question2=In the function y = 2x^2 plus 3x plus 4, what is the dependent variable?&question3=What is the derivative of y = x^2 plus 3&question4=If y' = x plus 3, what is the stationary point?&question5=What is the stationary point of y = (x plus 1)(x plus 2)&question6=Find the second derivative of y = 3x^2 plus6x plus 9&question7=What is the derivative of y = (2x plus 1)^2&question8=What is the derivative of y = (x plus 1)/(xplus2)&question9=Find and simplify the first derivative of y = (3x^2 plus 4x plus 3)^4&question10=Find f'(x) for f(x) = (x plus 1)(x plus 2)^2&question11=Factorise f'(x) = (x plus 2)^2 plus 2(x plus 2)(x plus 1)&question12=Find dm/du of m = (3u^2 plus 3u plus 7)(5u plus 3)&question13=Find y' of y = (4x^2)/(3 - x) ^3&question14=Find y' of y = (x^2plus1)^-1&question15=Find the first derivative of y = (2x plus 3)^2/(2x plus 1)&answer1=a&answer2=d&answer3=c&answer4=c&answer5=c&answer6=b&answer7=d&answer8=a&answer9=c&answer10=d&answer11=b&answer12=d&answer13=b&answer14=a&answer15=c&answer1a=To find the slope at any given point.&answer2a=x&answer3a=x^2 plus 3&answer4a=y = 3&answer5a=x = -1&answer6a=y' = 9&answer7a=y' = 2(2x plus1)&answer8a=y' = 1/(x plus 2)^2&answer9a=y' = (24x plus 16)(3x^2 plus 4x plus 3)^4&answer10a=f'(x) = (x plus 1)(x plus 2)^2 - 2(x plus 1)&answer11a=f'(x) = (2x plus 2)(x plus 2)^2&answer12a=dm/du = (6u plus 3)5&answer13a=y' = 8x/(3 - x)^6&answer14a=y' = -2x/(x^2 plus 1)^2&answer15a=y' = [2(2x plus 3) - 2(2x plus 1)]/(2xplus1)^2&answer1b=To find the x-intercept.&answer2b=2&answer3b=x^2&answer4b=x = 3&answer5b=x = -2&answer6b=y' = 6&answer7b=y' = 2(2x plus 1)^2&answer8b=y' = (x plus 1)(x plus 2)/(x plus 2)^2&answer9b=y' = 4(3x^2 plus 4x plus3)^3&answer10b=f'(x) = (x plus 1)(x plus 2)^2 - 2(x plus2)(x plus 1)&answer11b=f'(x) = (x plus 2)(3x plus 4)&answer12b=dm/du = (3u^2 plus 3)(5u plus 3)&answer13b=y' = 4x(x plus 6)/(x - 3)^4&answer14b=y' = -2x&answer15b=y' = [2(2x plus 3) plus 2(2x plus 1)]/(2xplus1)^2&answer1c=To find the y-intercept.&answer2c=3&answer3c=2x&answer4c=x = -3&answer5c=x = -3/2&answer6c=y' = 7&answer7c=y' = 4(2x plus 1)^2&answer8c=y' = 1/(x plus 2)&answer9c=y' = (24x plus 16)(3x^2 plus 4x plus 3)^3&answer10c=f'(x) = (x plus 1)(x plus 2)^2 plus 2(x plus 1)&answer11c=f'(x) = 2(x plus 2)^2(x plus 1)&answer12c=dm/du = (6u plus 3)(5uplus3) - 5(3u^2 plus 3u plus7)&answer13c=y' = 4/(3 - x)^2&answer14c=y' = -2x/(x plus 1)&answer15c=y' = [2(2x - 1)(2x plus 3)]/(2x plus 1)^2&answer1d=To find the area underneath the curve.&answer2d=y&answer3d=2x plus 3&answer4d=y = -3&answer5d=x = 3/2&answer6d=y' = 0&answer7d=y' = 4(2x plus 1)&answer8d=y'  = (2x plus 3)/(xplus2)^2&answer9d=y' = 4(3x^2 plus 4x plus3)^4&answer10d=f'(x) = (x plus 2)^2 plus 2(x plus 2)(x plus 1)&answer11d=f'(x) = 2(x plus 1)(x plus 2)&answer12d=dm/du = (6u plus 3)(5uplus3) plus 5(3u^2 plus 3u plus7)&answer13d=y' = 8x/(9 - 3x)^2&answer14d=y' = -2/(x^2 plus 1)&answer15d=y' = (2x plus 3)^2/(2x plus 1)